An experiment shows that a 250 ? ml gas sample has a mass of 0.430 g at a pressure of 736 mmhg and a temperature of 28 ? c.

What we're looking for here is the gas sample's molar mass given its mass, pressure, volume, and temperature. Recalling the gas law, we have

or


where R is 0.08206 L atm / mol K, P is the given pressure, T is the temperature, and V is the volume.

Before applying the values given, it is important to make sure that they are to be converted to have consistent units with that of R. 

Thus, we have

P = 736/ 729 = 0.968 atm
T = 28 + 273.15 = 301.15 K
V = 250/1000 = 0.250 L

Now, applying these converted values into the gas law, we have




Given that the mass of the sample is 0.430 g, we have

 


Thus, the gas sample has a molar mass of 43.9 g/mol.

It can be classified based on its