Hydrogen reacts with oxygen to form only water. if 16 grams of hydrogen is mized with 16 grams of oxygen, how much water can form

The balanced chemical equation will tell you the molar ratios in which hydrogen and oxygen react to form water:

2H2 + O2 > 2H2O

Then the ratio is 2 mol of H2 react with 1 mol of O2 and form 2 mol of H2O:

2 : 1 : 2

Now convert the given data into moles:

16 grams of H2 = 16 g / 2 g/mol = 8 mol

16 grams of O2 = 16 g / 16 g/mol = 1 mol.

Then you have that the 1 mol of oxygen will react with 2 moles of hydrogen and they will form  2 mol of H2O.

And you can calculate the mass of 2 moles of H2O by multiplying by its molar weigth: 18 g/mol.

2 mol H2O * 18 g/mol = 36 grams of water.

Then, the answer is 36 grams of H2O.

 

The reaction is:

When molecular hydrogen ( H2) and oxygen ( O2 ) is combined they form either water or hydrogen peroxide.
We have that mass of hydrogen is 16 g and mass of oxygen is 16 g. But O2 is the limiting reactant. Let`s see how much grams of hydrogen can be used for this reaction:
16 g O2 x (1 mol O2)/ (32 g O2) x ( 2 mol H2)/(1 mol O2)x (2 g H2) / (1 mol H2) = 2 g H2
Finally: 16 g + 2 g = 18 g.
C. 18 grams of water.