If 4.35 g of phosphoric acid are added to 5.25g of koh, what is the percent yield of the reaction if only 3.15g of potassium phosphate is isolated?

We are given with
4.35 g Phosphoric acid
5.25 g KOH
3.15 g K3PO4 produced

The reaction is
H3PO4 + 3KOH => K3PO4 + 3H2O

First, convert masses into moles.
Then, determine the limiting reactant.
Next, determine the maximum amount of K3PO4 that can be produced from the limiting reactant.
Lastly, calculate the percent yield by dividing the actual amount produced by the theoretical amount produced.

Temperature and pressure