How many moles of oxygen are required to produce 37.15 g co2?

37.15 g co2 = mol o2

As you have stated, the chemical equation for the reaction of plentiful oxygen with propane is:
C3H8 + 5O2 → 3CO2 + 4H2O
Therefore the molar ratio of oxygen to CO2 is 5:3. The moles of CO2 produced can be calculated using the equation:
moles = mass/RMM = 37.15 g / 44.0 g/mol = 0.844 mol
For every one mole of CO2 produced, 5/3 moles of O2 are consumed, therefore the moles of O2 required is:
0.844 mol * (5/3) = 1.41 mol
Hope this helps!

The answer to this is the 3rd choice!

The answer would be true