The combustion of 0.0272 mole of a hydrocarbon produces 1.9584 g h2o and 3.5927 g co2. what is the molar mass of the hydrocarbon?

Assuming that the hydrocarbon only contains hydrogen and carbon, then it will have the formula CxHy where x and y represents the number of carbon and hydrogen atoms, respectively. We proceed as follows:

CxHy + ((x+y/2)/2)O2 = xCO2 + y/2H2O

1.9584 g H2O ( 1 mol / 18.02 g ) ( 2 mol H / 1 mol H2O ) = 0.0272y
y = 8 mol H

3.5927 g CO2 ( 1 mol / 44.01 g ) ( 1 mol C / 1 mol CO2 ) = 0.0272x
x = 3 mol C

C3H8 = 44.11 g / mol

The answer for this question is d. none of these

Only one reactant yields 2 or more products. meaning you will only have 1 product and it will break down into 2 or more products. eg. h2o -> h2 + o2