Chemistry, 08.01.2020 19:31 kprincess16r
10.0 ml of a 0.100 mol lā1 solution of a metal ion m2+ is mixed with 10.0 ml of a 0.100 mol lā1 solution of a substance l. the following equilibrium is established:
m2+(aq) + 2l(aq) picture ml22+(aq)
at equilibrium the concentration of l is found to be 0.0100 mol lā1. what is the equilibrium concentration of ml22+, in mol lā1?
someone me
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10.0 ml of a 0.100 mol lā1 solution of a metal ion m2+ is mixed with 10.0 ml of a 0.100 mol lā1 solu...
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