How many grams of h2 are needed to react with 2.70 g of n2?

3H₂  +  N₂  →  2NH₃

mole of N₂ = mass ÷ molar mass
                  =  2.70g ÷ (14 × 2)
                  =  0.096 mol

mole ratio of N₂ : H₂
                      1  :  3

∴ if the moles of N₂ = 0.096 mol

then the mole of H₂ = 0.096 mol × 3
                                = 0.289 mol

Now, mass = mole × molar mass
∴ mass of H₂ needed to react = 0.289 mol × (1 × 2)
                                                = 0.579 g

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