What is the ph of 1.85 g of hcn (mm = 27.02) dissolved in 3.50 l of water?

PH is logarithmically related to the concentration of H+ ions. This will be the formula that will be used for this problem. We calculate as follows:

HCN = H+ + CN-

1.85 g HCN ( 1 mol / 27.02 ) ( 1 mol H+ / 1 mol HCN ) = 0.068 mol H+

Concentration = 0.068 / 3.50 = 0.02 M

pH = -log 0.02
pH = 1.71