Asample of a compound contains 32.0 g c and 8.0 g h. its molar mass is 30.0 g/mol. what is the compound’s molecular formula? ch3 ch4 c2h4 c2h6

First is solve the emperical formula of the given compound. first convert the given mass to moles.

moles C = 32 g ( 1 mole / 12 g ) = 8 / 3 moles = 2.667 moles C

moles H = 8 g ( 1 mole / 1 g ) = 8 moles

then divide the moles with lowest value to know the coefficient

C = 2.6667 / 2.6667 = 1
H = 8 / 2.6667 = 3
so the emperical formula is CH3, but it does not satisfy the molar mass

to satisfy it multiply it by 2, it will become C2H6 and the molar mass is 30

Ais your answer to this

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