Chemistry, 28.01.2020 10:31 Redhead667

How many more times intense is an earthquake that measures 8 on the richter scale than an earthquake that measures 5? explain your answer.

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Answer from: Olaf2018

The answer on edguinity is A magnitude 8 earthquake is 1,000 times more intense than a magnitude 5 earthquake. A magnitude 8 earthquake is 108 times more intense than a standard earthquake, while a magnitude 5 earthquake is 105 times more intense than a standard earthquake, and 108 ÷ 105 = 103. Each unit increase on the Richter scale corresponds to an intensity increase by a factor of 10. So from 5 to 8 on the Richter scale, the intensity increases by 103 = 1,000.

Answer from: zafarm2oxgpmx

The earthquake will be 1000 times more intense when it is measured 8 on the Richter scale.

Explanation: Richter scale is the numerical scale which measures the intensity of earthquake with the help of seismographic oscillations.

Each level on the Richter scale is 10 times stronger than the previous one.

Richter scale measuring 8 is three levels up than the value 5 on the scale.

Hence, the earthquake having 8 on the Richter scale will be ( 10 × 10 × 10) = 1000 times more intense than the earthquake having 5 on the Richter scale.

Answer from: Quest

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

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