Calculate the grams of oxygen in 90.0 g of cl2o

The correct answer is 16,576 g of .

Explanation:

First, we must calculate the molar mass (Mm) of and .

Mm = 32g

Mm = 86,9 g

Now we know we have 90 g of , so let's find out how many moles of there are in that amount.

90 g * = 1.036 mol

Now, in the formation reaction we have that 1 mole of reacts to obtain 2 moles of :

+ 2 -> 2

Taking the coefficients, we calculate the number of moles of that react:

1,036 mol * = 0,518 mol

Finally, we calculate the number of grams in the moles of that react:

0,518 mol * = 16,576 g

Have a nice day!

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8

5.6⋅10−^19  j

do you need the explaination?