(6.93 x 10 1 ) (2.0 x 10 -4 ) =

1.386 -2
13.86 x 10 -3
1.386 x 10 -2
1.4 x 10 -2

During trial 2, what allowed you to determine that aluminum was the limiting reactant? check all that apply. all of the copper dissolved. all of the aluminum dissolved. the solution turned clear. the number of grams of copper(ii) chloride used in the reaction was greater than the number of grams of aluminum. the molar ratio of copper(ii) chloride to aluminum was greater than 3: 2, the equation’s molar ratio.

Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife

What three things determine the shape and size of a puddle when water is poured out onto a surface