There are 342 g of sucrose in 1.00 mol of sucrose. what is the molar concentration (molarity) of a solution containing 171 g sucrose in 1.75 l solution?

The molarity of sucrose solution is 0.286 M

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Mass of solute (sucrose) = 171 g

Molar mass of sucrose = 342 g/mol

Volume of solution = 1.75 L

Putting values in above equation, we get:

Hence, the molarity of sucrose solution is 0.286 M

if you mean hydrogen and oxygen then water is the product

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml