Acontainer holds 1 mole of helium gas. the volume of the container is 2 liters and the pressure inside the container is 105.0 kpa. if the volume of the container is decreased to 1.5 liters, what will be the new pressure inside the container?

1 mole of helium gas
the volume of one mole of helium gas is V=22.4L (this is the so-called molar volume of any gas)
so the volume initial is V1= V+ Vcontainer =22.4L + 2L=24.4L
according to boyles Law
P1 /V1 = P2 /V2
and 1kPa = 0.009 atm
        105.0 kPa= 0.94 atm

so P2 = V2 x P1 / V1= 1.5 x 0.95  / 24.4 = 0.05 atm

Outermost (valence) electrons

Density and pressure