Calculate the number of grams of solute in 500.0 ml of 0.189 m koh.

of KOH is present in 500 mL of 0.189 M KOH solution.

Further Explanation:

The concentration is the proportion of substance in the mixture. The most commonly used concentration terms are as follows:

1. Molarity  

2. Molality  

3. Mole fraction  

4. Parts per million  

5. Mass percent  

6. Volume percent  

Molarity is a concentration term that is defined as the number of moles of solute dissolved in one litre of the solution. It is denoted by M and its unit is mol/L.

The formula to calculate the molarity of KOH is as follows:

                        ......(1)

Rearrange equation (1) to calculate the amount of KOH.

   ......(2)

The molarity of the KOH solution is 0.189 M or 0.189 mol/L.

The volume of KOH solution is 500 mL.

Substitute these values in equation (2)

The formula to calculate the mass of KOH is,

    ......(3)

The amount of KOH is 0.0945 mol.

The molar mass of KOH is 56 g/mol.

Substitute these values in equation (3)

So the mass of KOH is 5.292 g.

Learn more:

1. What is the mass of 1 mole of viruses: link

2. Determine the moles of water produced: link

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Solutions

Keywords: KOH, molarity, 500 mL, 5.292 g, mol/L, 0.189 M, molar mass, 56 g/mol, concentration, concentration terms, volume.

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3