Chemistry, 09.12.2019 18:31 inucornspineapple

What is the ratio of effusion rates of krypton and neon at the same temperature and pressure?

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The formula we use would be the graham's law. We do as follows:

E_Kr / E_Ne = sqrt ( M_Ne / M_Kr)

= sqrt ( 20.1797 g/mol / 83.798 g/mol )
= sqrt (0.24081)
= 0.4907

Hope this answers the question. Have a nice day.

Answer from: cooper2017

The ratio of effusion rates of krypton and neon is 0.49

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

We are given:

Molar mass of Neon = 20.18 g/mol

Molar mass of Krypton = 83.80 g/mol

By taking their ratio, we get:

$\frac{Rate_{Kr}}{Rate_{Ne}}=\sqrt{\frac{M_{Ne}}{M_{Kr}}}$

$\frac{Rate_{Kr}}{Rate_{Ne}}=\sqrt{\frac{20.18}{83.80}}\\\\\frac{Rate_{Kr}}{Rate_{Ne}}=0.49$

Hence, the ratio of rate of effusion of krypton and neon will be 0.49

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

Answer from: Quest

1. o2(g)as a product

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