A1.00g sample of an acid was dissolved in enough water to create 100.0ml of aqueous solution. titrate it with 15.00ml of 1.058m naoh. determine the formula mass of the acid, assuming two acidic protons per formula unit.

Given:
1.00 gram sample of an acid (x)
100 mL aqueous solution
15.00 mL NaOH
1.058 M NaOH 

To solve for the formula mass of the acid through dimensional analysis:

The final answer should be (g/mol)

Formula mass = (1 gram acid) / ( (15mL/1000mL NaOH/L) * 1.058 mol/L NaOH)

Therefore, the formula mass of the acid is 63.01 g/mol

D-no effect on the rate

If it releases 5 tons a day and there are 7 days a take that answer and multiply by 5 percent (0.05) to find the amount released in one week. leave a comment if you need more .