If 75.0 g silderite ore (feco3) is heated with an excess of oxygen, 45.0 g of ferric oxide (fe2o3) is produced. 4feco3(s) + o2(g) → 2fe2o3(s) + 4co2(g) what is the percent yield of this reaction?

Answer : The percent yield of the reaction is, 87.0 %

Solution : Given,

Mass of = 75.0 g

Molar mass of = 115.85 g/mole

Molar mass of = 159.69 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 4 mole of react to give 2 mole of

So, 0.647 moles of react to give moles of

Now we have to calculate the mass of

Theoretical yield of = 51.7 g

Experimental yield of = 45.0 g

Now we have to calculate the percent yield of the reaction.

Therefore, the percent yield of the reaction is, 87.0 %