When an aqueous solution of kbr is electrolyzed,
the following process occurs.
kbr + h2o → koh + br2 + h2
balance this equation and indicate the sum of
the coefficients of all of the species
1. four
2. twelve
3. eight
4. two
(no one seems to be answering me anymore lol)

KBr + H2O = KOH + Br2 + H2

So we know that we need a 2 on the left of kbr so it would equal the right Br.

=2KBr
 now put a 2 in front of KOH since we need a 2k on right side

Now we put a 2 infront of H2O which wil make 4 h's and 2 o's

2h2o 

now it is balanced

2KBr + 2H2O = 2KOH + Br2 + H2

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic