To eight significant figures, avogadro's constant is 6.0221367×1023mol−1. which of the following choices demonstrates correct rounding?

All of the following choices demonstrates correct rounding

Further explanation

There are general rules used in rounding numbers

1. Determine the rounded digit2. Pay attention to the digits afterward (right). If the digit shows the numbers 0, 1, 2, 3 or 4, then the digit to be rounded is fixed, and the digit on the right is 0 3. If the digit on the right shows the numbers 5, 6, 7, 8 or 9, then the digit to be rounded is added to one, and the digit on the right side is made all 0

for example, In rounding the nearest hundreds number, then we see the digit in the number tens (right of the digit hundreds), if it is worth 0, 1, 2, 3 or 4, then it remains, but if it shows numbers 5, 6, 7, 8 or 9, then the digit to be rounded is added one, and the right-hand side is 0

Choice of answer we add from the problem above:

6,022 × 10²³mol⁻¹

6.0 × 10²³mol⁻¹

6,02214 × 10²³mol⁻¹

For the Avogadro number of 6.0221367 × 10²³mol⁻¹

1. If we round into a 4 digit significant number, we see the digit after the number from the 4th digit of the 6.022 number (i.e. 2)

After this 4th digit we see number 1 so the rounding remains to be: 6,022

2. For Avogadro numbers on rounding to 2 digits, because the number after 0 at number 6.0 is 2 then the rounding is fixed so that it is worth 6.03. For Avogadro numbers in rounding to 6 digits, because the number after 3 at number 6.0221367 is 6 then rounding up so that it is worth 6.02214

So all of the answer choices are correct

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Keywords: round up, round down, the rounded digit

And a) oxygen i believe

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