A5.0 gram sample of lead and a 3.2 g sample of iron are placed into 367 ml of water. what will be the new volume level of water in units of ml? the density of lead is 11.34 g/cc and the density of iron is 7.874 g/cc.

Volume = mass/density 
Lead: v=5.0g/11.34g/cc = 0.440cc
For lead, the new volume level of water will be 367+0.440= 367.440ml

Iron: v=3.2g/7.874g/cc = 0.406cc
For Iron, the new volume level of water will be 367+0.406= 367.406ml 

If you add both, then it will be 367+0.406+0.440= 367.846 mL

First find the volume of each sample and then add that to 367ml of water. 

I hope that helps.