10. lead nitrate can be decomposed by heating. what is the percent yield of the decomposition reaction if 15.6 g pb(no3)2 are heated to give 9.4 g of pbo? 2pb(no3)2(s) → pbo(s) + 4no2(g) + o2(g) *
a. 59%
b. 73%
c. 82%
d. 90%

First, the equation is unbalanced:
2Pb(NO₃)₂ → 2PbO + 4NO₂ + O₂
Moles of Pb(NO₃)₂ = 15.6 / (207 + 2(14 + 16 x 3))
Moles of Pb(NO₃)₂ = 0.047
Theoretical yield = 0.047 moles
Theoretical yield = 0.047 x (207 + 16)
Theoretical yield = 10.48

Percentage yield = (9.4. / 10.48) x 100
Percentage yield = 89.6%

The answer is D