What is the expected freezing point of a 0.50 m solution of na2so4 in water kf for water is 1.86°c/m?

The expected freezing point of a 0.50 m solution of sodium sulfate is -0.93°C.

Explanation:

where,

=depression in freezing point =

= freezing point constant

m = molality

we have :

=1.86°C/m ,

m = 0.50 m

Freezing point of pure water = T =  0°C

Freezing point of solution =

The expected freezing point of a 0.50 m solution of sodium sulfate is -0.93°C.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !

honesty and integrity.

inspire others.

commitment and passion.

good communicator.

decision-making capabilities.

accountability.

delegation and empowerment.

creativity and innovation.

here are the traits of a good leader.i'm not going to give you the examples so you can copy right it.that's illegal but i hope that this you out.