Sulfuric acid (h2so4) is a very strong diprotic acid. if 0.054 moles of sulfuric acid is mixed with water to make 667 milliliter of solution, what is the molarity of h+?
answer in units of m doing mole/liter doesn't work

As, using formula0.054/(.667/18)
=.o54/.037
=1.45 approx

so the answer

The answer is 0.612M

Find the molarity of the diprotic acid.
667ml ÷ 1000ml = 0.667L
M = 0.054 ÷ 0.667 = 0.08095952023 = 0.081 M H2SO4
There are 2 H+ for every one H2SO4, so the molarity of H+ is twice the molarity of the acid.
2 x 0.081M = 0.162M

Outermost (valence) electrons