In the following balanced neutralization reaction equation, how many moles of ca(oh)2 are required to completely neutralize 1.2 moles of hi)
2hi + ca(oh)2 --> cal + 2h2o

2HI + Ca(OH)2 --> Cal + 2H2O. According to stoichiometry, 2 moles of HI reacts with 1 mole of Ca(OH)2. Therefore, 1.2 moles of HI will react with = 1.2/2 = 0.6 moles of Ca(OH)2. Hope this helps.

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True is ur answer : )