![\frac{[HCOO^-]_{eq}}{[HCOO^-]_{eq}+[HCOOH]_{eq}} \times 100 = \frac{[HCOO^-]_{eq}}{[HCOO^-]_{eq}+[HCOO^-]_{eq}}](/tpl/images/0200/7629/df44f.png)
![\frac{[HCOO^-]_{eq}}{2[HCOO^-]_{eq}} \times 100 = 50 \%](/tpl/images/0200/7629/5b79f.png)
100 ml of 1.0 m formic acid (hcooh) is titrated with 1.0 m sodium hydroxide (naoh).
the approx...
Chemistry, 26.08.2019 23:50 noahprice0519
100 ml of 1.0 m formic acid (hcooh) is titrated with 1.0 m sodium hydroxide (naoh).
the approximate pka is 4 at the pka, what fraction of the carboxyl group will have been converted to coo-?
Answers: 1
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