How many grams of sodium chloride, nacl, result from the reaction shown in the following equation, fecl3 + 3naoh

175.33 g.

Explanation:

The balanced equation of reaction is given below;

FeCl3 + 3NaOH > Fe(OH)3 + 3NaCl.

From the balanced equation of reaction we can see that one mole of FeCl3 reacts with three moles of sodium hydroxide to produce 3 mole of sodium chloride,NaCl and one mole of Fe(OH)3.

To calculate for the number of grams we will be needing the molar mass of Sodium chloride.

Molar mass of sodium chloride,NaCl= 22.989769 + 35.453 = 58.442769 grams per mole. Approximately, 58.443 grams per mole.

Therefore, the number of moles,n= mass/ molar mass. Recall that we have three(3) moles of Sodium chloride as the product. Hence,

3 mol = mass(in grams)/ molar mass(in grams per mol).

==> 3 = mass(in grams)/ 58.443 (grams per mol).

===> Mass in grams = 58.443 (grams per mol) × 3 mol.

Mass in grams = 175.33 grams.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the volume increases