Gaseous c2h4 reacts with o2 according to the following equation:
c2h4 (g) + 302 -> 2co2 + h2o (g)
what volume of oxygen gas at stp is needed to react with 5.75 mol of c2h4?
a) 17.3 l
b) 42.9 l
c) 3.86 x 10^2 l
d) 1.29 x 10^2 l
e) not enough information is given to solve the problem.

Each mole of gas occupies 22.4 L at STP.

Liters of gas = 17.25 x 22.4

= 3.86 x 10² L

Your correct answer is C 3.86 x 10^2 L

Explanation:

odds are decent that your handwriting right now looks a little bit different than it did five years ago, and will look different again in five more. when i look back through my notebooks from middle school to now, i see a long, slow progression from meticulous and teeny letters to bigger, sloppier ones, plus a few side detours: sometime in high school, for example, i decided those loopy cursive lowercase f’s were just the coolest, adopting them as the lone rep for cursive in my otherwise all-print handwriting.

explanation:

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.