What is the total pressure on the gas after the 760 mm hg has been added?
first phase atmospheric pressure= 760 torr gas volume= 60 ml (760 mm hg added to 2nd phase) second phase atmospheric pressure= 760 torr gas volume= 30 ml **image looks like a j. in the 2nd phase, there is 760 mm that is half of the j** if that makes any sense.
i am confused on how you solve the problem considering the torr and ml and mm and mmhg

1520 torr = 1520mmHg = 2 atm.

Explanation:

Please note that it is just basic conversion.

1 torr = 1mmHg

1 atm = 760mmHg = 760 torr

As per the question,

FIRST PHASE:

760 torr pressure is applied which gave = 60mL volume to gas.

SECOND PHASE:

760mmHg pressure is applied which gave = 30mL volume to gas

Since we know that 1mmHg = 1 torr.

Therefore, total gas pressure = 760 + 760 = 1520 torr OR 1520mmHg

here's the link to your question!

explanation:

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.