Determine how many moles of ba(oh)2 are required to completely neutralize 0.432 mole of hc2h3o2.

We need 0.216 moles of Ba(OH)2 to completely neutralize 0.432 moles of HC2H3O2.

Explanation:

2 CH3COOH + Ba(OH)2 = Ba(Ch3COO)2 + 2 H2O

0.432moles CH3COOH x [1 mol Ba(OH)2/ 2 moles CH3COOH]  = 0.216 moles Ba(OH)2

answer; ///(d) the correct answer is double or triple

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.