Use the equation qliquid = m × c × ΔT to calculate the heat gained by the cold liquid. Use the specific heat for the liquid you selected. Use the equation qwater = m × c × ΔT to calculate the heat lost by the hot water. Show your work using the problem-solving method shown in previous rubrics.

Complete question :

Use the equation qliquid = m × c × ΔT to calculate the heat gained by the cold liquid. Use the specific heat for the liquid you selected.

m = 248.9 g ; T = 72.6°C ; C = 3.73 j/g°C

Use the equation qwater = m × c × ΔT to calculate the heat lost by the hot water. Show your work using the problem-solving method shown in previous rubrics.

M = 237 g ; T = 41.2°C ; C = 4.184 j/g°C

Quantity of heat gained = 67401.6 Joules

Quantity of heat lost by hot water = 40854.25 Joules

Explanation:

The heat gained by cold liquid :

Q = m × c × ΔT

m = 248.9 g ; T = 72.6°C ; C = 3.73 j/g°C

Q = 248.9 * 3.73 * 72.6

Q = 67401.6 Joules

Quantity of heat gained = 67401.6 Joules

Heat lost by hot water :

m × c × ΔT

M = 237 g ; T = 41.2°C ; C = 4.184 j/g°C

Q = 237 * 41.2 * 4.184

Q = 40854.25 Joules

Quantity of heat lost by hot water = 40854.25 Joules

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%