1. Calculate AH for the reaction: C2H4 (g) + H2 (g) | C2H6 (g), from the following Data. (1) C2H4 (g) + 3 O2 (g) 2 CO2 (g) + 2 H2O (1)
AH, = - 1411. kJ
(2)
C2H6(g) + 342 02 (g) 2 CO2 (g) + 3 H20 (1)
AH, = - 1560. kJ
(3)
H2(g) + 1/2O2(g) | H2O (1)
AH3 = -285.8 kJ
1/4

Ametal with a large number of free flowing electrons most likely has good conductivity

The answers are 3.c kelvin4.b liquids only

Ibelieve it is b. proton.hope my answer has you : )

Reaction involved in present system is :   c12h22o11 + h2o → 2 c6h12o6the reaction system is obeying following rate law:   rate = k[c12h22o11]thus, it is a first order reaction.now, for 1st order reactionrate constant (k) =  given: initial conc. = 3.0 g, final conc. = 2.7 g, t = 2.5 h∴rate constant (k) =  ∴ k = 0.04215 h-1now, for 1st order reaction, half life = 0.693/k = 0.693/0.04215 = 16.4 hthus correct answer is option b