Complete each nuclear reaction equation. Superscript 14 subscript 7 upper N plus superscript 4 subscript 2 upper H e right arrow superscript question mark subscript 8 upper O plus superscript 1 subscript question upper H.

Nitrogen transmutes to form an isotope of oxygen. The superscript for oxygen is?

The subscript for hydrogen is?

Superscript 59 subscript question mark upper C o plus superscript 1 subscript 0 n right arrow superscript 60 subscript 27 upper C o.

Cobalt-59 accepts a neutron to form a new isotope. The subscript for cobalt is?

it is 17 then 1 then finally 27

Explanation:

Nitrogen transmutes to form an isotope of oxygen. The superscript for oxygen is 17

The subscript for hydrogen is 1

Cobalt-59 accepts a neutron to form a new isotope. The subscript for cobalt is 27

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%