subject
Chemistry, 18.04.2021 15:40 samantha9014

Hemos preparado una disolución de cloruro de cobre (II) en agua disolviendo 12 g de cloruro de cobre (II) en 98 g de agua, de forma que una vez completamente disuelta ocupa un volumen de 100 cm^3. Calcula la concentración en % en peso y en g/l. ¿Qué concentración tendrán 10 cm^3 de esa disolución? Si evaporamos todo el agua que hay en los 10 cm^3 de disolución, ¿cuánto cloruro de cobre (II) se recupera? ¿Qué tendríamos que hacer para que la disolución esté más diluida?

ansver
Answers: 2

Another question on Chemistry

question
Chemistry, 22.06.2019 12:00
What are the first two quantum numbers for the electrons located in subshell 4d? what are the first three quantum numbers for the electrons located in subshell 2s? how many electrons can be held in a sublevel l = 3? how many electrons can be held in the energy level n = 4? how many electrons in an atom can share the quantum numbers n = 4 and l = 3?
Answers: 1
question
Chemistry, 23.06.2019 01:30
Astudent states that 9.0 g of baking soda will form an unsaturated solution in 100 g of water. what do you need to know to decide whether this statement is correct? a. the temperature of the water and the molar mass of baking soda b. the percent by volume of the solution and the solubility of baking soda c. the temperature of the water and the solubility of baking soda at that temperature
Answers: 1
question
Chemistry, 23.06.2019 01:30
Which statement justifies that hydrogen peroxide (h2o2) is a polar molecule? the o – h bond is nonpolar and the molecule is asymmetric. the o – h bond is nonpolar and the molecule is symmetric. the o – h bond is polar and the molecule is asymmetric. the o – h bond is polar and the molecule is symmetric.
Answers: 1
question
Chemistry, 23.06.2019 03:10
Which is true according to the law of conservation of energy
Answers: 1
You know the right answer?
Hemos preparado una disolución de cloruro de cobre (II) en agua disolviendo 12 g de cloruro de cobre...
Questions
question
Chemistry, 19.08.2019 22:30
question
English, 19.08.2019 22:30