A 20.0 g lead ball is heated in a Bunsen burner to 705oC. It is then dropped into a 500.0 g water bath. What is the initial temperature of the water if the final temperature is 35 oC? The Cp of lead is 0.13 J/goC. [Remember: CH2O = 4.18 J/g○C]

Solve this in the following order:
Part A: What is the energy lost of the metal? (round to the nearest WHOLE number, type the ABSOLUTE value of energy lost)
Part B: What is the water's temperature change? (round to ONE decimal place!)
Part C: What was the water's initial temperature? (final answer should include ONE decimal place!)

samuel de champlain. in 1608, king henry iv sponsored pierre dugua, sieur de mons and samuel de champlain as founders of the city of quebec with 28 men. this was the second permanent french settlement in the colony of canada.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

the answer is d.) potassium