What is the molarity of .65 L of solution containing 63 grams of NaCl? (dont forget to convert grams to moles)

1.66 M

Explanation:

Molarity = moles/L solution

We have the following data:

mass NaCl = m = 63 g

volume of solution = V = 0.65 L

Thus, we first convert the mass to moles with the molar mass of NaCl (MM):

MM(NaCl) = 23 g/mol Na + 35.4 g/mol Cl = 58.4 g/mol

moles NaCl = m/MM = 63 g/(58.4 g/mol)= 1.08 mol

Finally, we divide the moles into the volume of solution to calculate the molarity:

M = moles NaCl/V = 1.66 mol/L

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