1. What is the molarity of an HCl solution if 50.0 mL of it is neutralized in a titration by 40.0 mL of 0.400 M NaOH? (0.32)

C1 * V1 = C2 * V2

Explanation:

Where ‘C’ and ‘V’ refer to concentration and volume, ‘1’ and ‘2’ to solution 1 and 2 respectively. So, if ‘1’ refers to the HCl solution, we want to solve this equation for C1.

V1 = (C2*V2)/C1 = (0.4 * 50)/40 = 0.5 M

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