72.3 g of ice at -15.0 o C has heat energy added to it until it becomes steam at 145 o C. Calculate the total amount of heat energy needed (in Joules) to accomplish this.

H = 226,311.66J

Explanation:

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In this case, according to the thermodynamic path ice takes up to steam:

1. Ice (-15°C) --> Ice (0°C) H1

2. Ice (0°C) ---> Water (0°C) H2

3. Water (0°C) --> Water (100°C) H3

4. Water (100°C) --> Steam (100°C) H4

5. Steam (100°C) --> Steam (145°C) H5

It is possible for us to infer that H1, H3 and H5 are computed by means of the mass, specific heat and change in temperature as sensible heat. On the flip side, H2 and H4 are computed as latent heat. Thus, we proceed as follows:

Then, we add them up to obtain the total heat:

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1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: