Chemistry, 14.04.2021 17:10 eelebron0905
Cu (s) + ½ O2 (g) → CuO (s)
CuO(s) + Cu(s) → Cu2O(s) ΔH = -22 kJ/mol
2CuO(s) → Cu2O(s) + ½ O2(g) ΔH = +115 kJ/mol
Answers: 3
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Cu (s) + ½ O2 (g) → CuO (s)
CuO(s) + Cu(s) → Cu2O(s) ΔH = -22 kJ/mol
2CuO(s) → Cu2O(s)...
2CuO(s) → Cu2O(s)...
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