1. The pressure on 2.50L of an enclosed gas changes from 105kPa to 40.5kPa. If the temperature remains unchanged
what is the new volume?
2. A gas with a volume of 3.50L at a pressure of 200kPa is
allowed to expand to 14.0L. If the temperature remains
unchanged what is the new pressure?
3. A sample of gas occupies 5.00L at a temperature of 27
degrees celsius. What will its volume be at 127 degrees
celsius if the pressure remains the same?

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :