80 grams of water releases 2550 joules of heat. What is the temperature change of the water? Heat capacity of water is 4.2 J/g°C.

7.59°C

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat (joules)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

According to this question;

m = 80g

c = 4.2 J/g°C.

Q = 2550J

∆T = ?

Using Q = m × c × ∆T

∆T = Q/mc

∆T = 2550 ÷ (80 × 4.2)

∆T = 2550 ÷ 336

∆T = 7.589°C

The change in temperature of water = 7.59°C.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.

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explanation: