Determine the volume of the product containing carbon produced when 15.0 g of C2H2 are reacted with an excess of oxygen gas

25.8 L

Explanation:

Step 1: Write the balanced equation for the complete combustion of acetylene

C₂H₂ + 2.5 O₂ ⇒ 2 CO₂ + H₂O

Step 2: Calculate the moles corresponding to 15.0 g of C₂H₂

The molar mass of C₂H₂ is 26.04 g/mol.

15.0 g × 1 mol/26.04 g = 0.576 mol

Step 3: Calculate the moles of CO₂ produced from 0.576 moles of C₂H₂

The molar ratio of C₂H₂ to CO₂ is 1:2. The moles of CO₂ produced are 2/1 × 0.576 mol = 1.15 mol.

Step 4: Calculate the volume corresponding to 1.15 moles of CO₂

At standard temperature and pressure, 1 mole of CO₂ occupies 22.4 L.

1.15 mol × 22.4 L/1 mol = 25.8 L