Rank these transition metal ions in order of decreasing number of unpaired electrons. If two ions have the same number of unpaired electrons Fe^3 , Mn^4+ , V3+ , Ni^2+ , Cu^+

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Explanation:

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom.

Fe: 26:

: 5 unpaired electrons

Mn: 25:

: 3 unpaired electrons

V: 23:

: 2 unpaired electrons

Ni : 28 :

: 2 unpiared electrons

Cu : 29 :

: 0 unpaired electrons

Thus the order of decreasing number of unpaired electrons:

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1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

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