Calculate the number of c, h, and o atoms in 1.75 g of squaric acid

As far as I remember, the needed formula for squaric acid is C4H2O4.
According to this one mole should be  114.06 g., which means we have 0.015mol of this acid.
Then we can  easly calculate : 4(0.015) = 0.06 mol for both for Carbon and Oxygen and 0.03 mol of Hydrogen.
To get more clear answer, we multiply by avogadros : 
6.022 x 10^23. Hope everything is clear! regards