Calculate magnetic moment of a divalent ion in aqueous solution, if the electronic configuration is [Ar] 3d5 .

5.47 B.M

Explanation:

✓We were given electronic configuration of argon as [Ar] 3d5.

✓This is a divalent ion. It has atomic number of 25.

✓magnetic moment can be calculated using below expresion

√[n(n+2)] eqn(1)

✓ It has 5 unpaired electrons. Then n= 5

✓ [n(n+2)]

✓ substitute the ( n= 5) into eqn(1)

Then magnetic moment= [n(n+2)]

= [ 5(5+2) ]

= 5.47BM

the answer is d.) potassium