Chemistry, 10.04.2021 05:50 doughboy123
Liquid hydrazine, N2H4(l), is a rocket fuel. It combusts in oxygen gas to form nitrogen gas and liquid water:
N2H4(l) + O2(g) -> N2(g) + 2H2O(l)
Use the following thermochemical equations to calculate the enthalpy change for the combustion of liquid hydrazine:
2NH3(g) + 3N2O(g) -> 4N2(g) + 3H2O(l) ΔH = -1010kJ
N2O(g) + 3H2(g) -> N2H4(l) + H2O(l) ΔH = -317kJ
2NH3(g) + 0.5O2(g) -> N2H4(l) + H2O(l) ΔH = -143kJ
H2(g) + 0.5O2(g) -> H2O(l) ΔH = -286kJ
Edit: For reference, the book says the answer is ΔH = -623kJ
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