How many Faraday is needed to deposit 0.2 g of Calcium (Ca) from CaCl2 solution using electrolysis process.

0.01 faraday

Explanation:

We'll begin by writing the balanced equation. This is illustrated below:

CaCl₂ (aq) —> Ca²⁺ (aq) + 2Cl¯ (aq)

Ca²⁺ (aq) + 2e —> Ca

Molar mass of Ca = 40 g/mol

Mass of Ca from the balanced equation = 1 × 40 = 40 g

1 mole of electron (e) = 1 faraday

2 moles of electrons (e) = 2 × 1 faraday

2 moles of electrons (e) = 2 faraday

From the balanced equation above,

40 g of Ca was deposited by 2 faraday.

Therefore, 0.2 g of Ca will be deposited by = (0.2 × 2)/40 = 0.01 faraday.

Thus, 0.01 faraday is needed for the reaction.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :