A 10.0 mL sample of H2SO4 was exactly neutralized by 23.5 mL of 1.00 M KOH. Calculate the molarity of the acid. H2SO4(aq) + KOH(aq) —> K2SO4(aq) + H2O(l)

1.175 M

Explanation:

The balanced reaction is:

First we calculate how many moles of KOH reacted, using the given concentration and volume:

Then we convert moles of KOH to moles of H₂SO₄, using the stoichiometric coefficients of the balanced reaction:

Finally we calculate the molarity of the acid:

2b2t

explanation:

2b2t