If I have 21 moles of gas held at a pressure of 780 kPa and a temperature of 900 K, what is the volume of the gas? PV=nRT R=8.314 L*kPa/mol*K*
PLS HELP!!

2.0 x 10^-2 L

Explanation:

PV=nRT

Substitute values into the ideal gas equation.

P = 780 kPa

V = ?

n = 21 mol

R = 8.314 L-kPa/mol-K

T = 900 K

(780 kPa)(V) = (21 mol)(8.314 L-kPa/mol-K)(900 K)

V = (21 mol)(8.314 L-kPa/mol-K)(900K) / (780 kPa)

V = 201.4561...

Round to sig figs.

V = 2.0 x 10^2 L

8

explanation:

each principal energy level above the first contains one s orbital and three p orbitals. a set of three p orbitals, called the p sublevel, can hold a maximum of six electrons. therefore, the second level can contain a maximum of eight electrons - that is, two in the s orbital and 6 in the three p orbitals.

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