If 50.0 g of silicon dioxide is heated with an excess of carbon, 27.9 g of silicon carbide is produced. What is the percent yield of the reaction

The percent yield of the reaction is 83.5 %

Explanation:

The given balanced equation is

is the limiting reagent as it limits the formation of product and is the excess reagent.

According to stoichiometry :

60.08 g of produce = 40.11 of

Thus 50.0 of will produce=  of

 Experimental yield of SiC = 27.9 g

Percent yield =

Thus  percent yield of the reaction is 83.5 %

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole